1.

The pH of 0.1 M solution of an organic acid is 3.0. Calculate the dissociation constant of the acid.

Answer»


SOLUTION :`RCO O H HARR RCO O ^(-) + H^(+)`
`[H^(+)]=[RCO O^(-)]=10^(-3)M(.:' pH =3)`
`[RCO OH] = 0.1 - 10^(-3) ~~ 0.1 M`
`K_(a) = ([RCO O^(-)][H^(+)])/([RCO OH])=(10^(-3)xx10^(-3))/(0.1)=10^(-5)`.


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