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The pH of 0.1 M solution of an organic acid is 3.0. Calculate the dissociation constant of the acid. |
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Answer» `[H^(+)]=[RCO O^(-)]=10^(-3)M(.:' pH =3)` `[RCO OH] = 0.1 - 10^(-3) ~~ 0.1 M` `K_(a) = ([RCO O^(-)][H^(+)])/([RCO OH])=(10^(-3)xx10^(-3))/(0.1)=10^(-5)`. |
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