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The pH of 0.1 M solution of cyanic acid (HCNO) is 2.34. Calculate the ionization constant of the acid and its degree of ionization in the solution . |
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Answer» Solution :`HCNO HARR H^(+)+CNO^(-)` `pH = 2.34 "means" - LOG [H^(+)]= 2.34 or log [H^(+)]=2.34 or log [H^(+)]=-2.34 = bar(3).66` or `[H^(+)] ="Antilog" bar(3).66 = 4.57 xx 10^(-3) M` `[CNO^(-)]=[H^(+)]=4.57 xx 10^(-3) M` `K_(a)=((4.57xx10^(-3))(4.57xx10^(-3)))/(0.1)=2.09xx10^(-4)` `alpha = sqrt(K_(a)//C)=sqrt(2.09xx10^(-4)//0.1)=0.0457`. |
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