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The pH of 0.1 M solution of cyanic acid (HCNO) is 2.34. Calculate the ionization constant of the acid and its degree of ionization in the solution. |
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Answer» Solution :`HCNO LEFTRIGHTARROW H^+ + CNO^-` pH=2.34 means `-log[H^+]=2.34 or log[H^+]=-2.34=3.86` or `[H^+]=` ANTILOG `3.86=4.57 times 10^-3 M` `[CNO^-]=[H^+]=4.57 times 10^-3M` `K_a=((4.57 times 10^-3)(4.57 times 10^-3))/0.1=2.09 times 10^-4` `a=SQRT(K_a//C)=sqrt(2.09 times 10^-4//0.1)=0.0457` |
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