1.

The pH of 0.10 M NH_(3) solution (K_(b)=1.8xx10^(-5)) is :

Answer»

`2.87`
`11.13`
1
13

Solution :`[OH^(-)]=sqrt(cK_(b))=sqrt(0.10xx1.8xx10^(-5))`
`=1.34xx10^(-3)`
`[H^(+)]=(1xx10^(-14))/(1.34xx10^(-3))=7.46xx10^(-12)`
`pH=-log [H^(+)]`
`=-log(7.46xx10^(-12))`
`=11.13`


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