1.

The pH of 10^(-4) M KOH solution will be

Answer»

4
11
`10.5`
10

Solution :`KOHtoK^(+) +OH^(-)`
` 10^(-4) M10^(-4) M`
` thererfore[OH^(-)] = 10^(-4) M `
` thereforepOH=- log_(10)[OH^(-)]=- log_(10) (10^(-4)) = 4`
` therefore pH= 14-4= 10`


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