1.

The pH of 10^(-5) M KOH solution will be

Answer»

9
5
19
none of these

Solution :`KOHtoK^(+)OH^(-)`
`10^(-5)"M "10^(-5)"M "10^(-5)"M"`
`[OH^(-)]=10^(-5)M`
`pH=14-pOH`
`pH=14-(-LOG[OH^(-)])`
`=14+log[OH^(-)]=14+log10^(-5)`
`=14-5=9`


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