1.

The pH of 10-5 M KOH solution will be ……… (a) 9 (b) 5 (c) 19 (d) none of these

Answer»

(a) 9

KOH → K+ + OH

10-5 M 10-5 M 10-5

[OH ]= 10-5

pH = 14 – pOH 

pH = 14 – (-log [OH-]) 

= 14 + log [OH-

= 14 + log10-5 

= 14 – 5 

= 9



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