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The pH of 10-5 M KOH solution will be ……… (a) 9 (b) 5 (c) 19 (d) none of these |
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Answer» (a) 9 KOH → K+ + OH- 10-5 M 10-5 M 10-5 M [OH ]= 10-5 M pH = 14 – pOH pH = 14 – (-log [OH-]) = 14 + log [OH-] = 14 + log10-5 = 14 – 5 = 9 |
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