1.

The pH of 10^(-8) M HCl solution is :

Answer»

8
`6.9586`
more than 8
slightly more than 7.

Solution :Concentration of `HCl = 10^(-8)M`
`THEREFORE [H^(+)]=10^(-8)M`
Ionic product of water, `K_(w)=[H^(+)][OH^(+)]=10^(-14)`
or `[H^(+)]=[OH^(-)]=10^(-7)M`
`therefore`TOTAL `[H^(+)]=(10^(-8)+10^(-7))M`
`=10^(-7)(10^(-1)+1)M`
`=1.1xx10^(-7)M`
`pH=-log[H^(+)]`
`=-log (1.1xx10^(7))`
`=6.9586`.


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