1.

The pH of 10^(-8) M HCl solution is

Answer»

8
more than 8
between 6 and 7
slightly more than 7

Solution :From `H_(2)O, [H^(+)]=1xx10^(-7)M`
From HCl, `[H^(+)]=1xx10^(-8)M`
`THEREFORE`Total `[H^(+)]=(1xx10^(-7)+1xx10^(-8))M`
`=(1xx10^(-7)+0.1xx10^(-7))M=1.1xx10^(-7)M`
`therefore pH =-log (1.1xx10^(-7))=6.9586`


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