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The pH of 2.5xx10^(-1) M HCN solution (K_(a)=4xx10^(-10)) is : |
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Answer» `2xx10^(-5)` `= sqrt(4xx10^(-10)xx2.5xx10^(-1))` `=sqrt(1xx10^(-10))=1xx10^(-5)` `therefore PH =-log(10^(-5))=5` |
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