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The pH of a `0.005 M H_(2)SO_(4)` solution isA. `3.3`B. `5.0`C. `2.0`D. `4.0` |
Answer» Correct Answer - C Since `H_(2)SO_(4)` is a strong acid and 1 mol of `H_(2)SO_(4)` gives 2 mol of `H^(+)` ions, we have `C_(H^(+))=2xxC_H_(2)SO_(4))=(2)(0.005 M)` `=0.01` `=1xx10^(-2)M` `pH= -"1og"C_(H^(+))/(mol L^(-1))= -1og(1xx10^(-2))` `= 2.0` |
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