1.

The pH of a 0.01 M solutions of acetic acid having degree of dissociation 12.5% is

Answer»

5.623
2.903
3.723
4.509

Solution :`[H^(+)] = C alpha = 0.01 xx (1.25)/(100)`
`H^(+) = 1.25 xx 10^(-3)`, PH = between 2 or 3 = 2.90.


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