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The pH of a sample of vinegar is 3.76. Calculate the concentration of hydrogen ion in it. |
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Answer» Solution :pH=-LOG `[H^+]` = -3.76 `THEREFORE` log `[H^+]`=-3.76 = `bar4.24` `therefore [H^+]`= Antilog `(bar4.24)` `=1.7378xx10^(-4) = 1.74xx10^(-4)` M |
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