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The pH of a sodium acetate–acetic acid buffer is 4.50. Calculate the ratio [CH3COO-]/[CH3COOH]. |
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Answer» THE EQUATION THAT WILL BE USED IS THE HENDERSON-HESSELBACH EQUATION.
pH=pka + LOG [BASE]/[ACID] IN THE SYSTEM THE BASE IS CH3COO— WHILE THE ACID IS CH3COOH. • THE pKa OF ACETIC ACID IS 4.75. 4.50 = 4.75 + LOG [CH3COO—] / [CH3COOH]
4.50-4.75= LOG [CH3COO—] / [ CH3COOH] -0. 25 = LOG [CH3COO—] / [CH3COOH]
[CH3COO—] / [CH3COOH] = O. 56 I HOPE THIS ANSWER WILL HELPFULL TO YOU. PLS MARK ME AS BRAINBRAINLIEST
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