The pH of a solution obtained by mixing 100 mL of a solution pH=3 with 400 mL of asolution of pH=4 is

The pH of a solution obtained by mixing 100 mL of a solution pH=3 with

1.	The pH of a solution obtained by mixing 100 mL of a solution pH=3 with 400 mL of asolution of pH=4 is
Answer» 3- log 2.8 7- log 2.8 4- log 2.8 5- log 2.8 Solution :`N_(1)V_(1)+N_(2)V_(2)=N_(3)(V_(1)+V_(2))` `10^(-3)xx100+10^(-4)xx400=N_(3)(100+400)` or, `N_(3)=(0.1+0.04)/(500)=(0.14)/(500)=2.8xx10^(-4)M` `pH =-log (2.8xx10^(-4))=4-"log"2.8`