1.

The pH of a solution of AgCI(s) with solubility product 1.6 xx 10^(-10) in 0.1 M Nacl solution would be :

Answer»

Zero
`1.26 XX 10^(-5)M`
`1.6 xx 10^(-9) M`
`1.6 xx 10^(-11) M`

Solution :`AgCl hArr AG^(+) + Cl^(-)`
`S hArr S + 0.1`
`K_(sp) = [Ag^(+)][Cl^(-)]`
`1.6 xx 10^(-10) = S xx (S + 0.1) = S xx 0.1`
`1.6 xx 10^(-9) = S`


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