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The pH of aqueous NaOH is 13. What weight of solute is present in 500 ml solution ? |
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Answer» Solution :GIVEN PH = 13, pOH = 14 - 13 = 1, `[OH^(-)] = [NaOH] = 10^(-1)=0.1 M` Gram molecular mass (GMW) of NaOH = `40 g mol^(-1)` Weight of solute present in IL solution=`M xxGMV =(1)/( 10 ) xx 40 =4` The weight of NaOH present in 500 ml solution = 2 grams. |
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