The pH of basic buffer mixtures is given by pH = pK_(a) + log.(["Base"])/(["Salt"]), whereas pH of acidic buffer mixtures is given by : pH = pK_(1) + log.(["Salt"])/(["Acid"]). Addition of little acid or base although shows no change in pH for all practical purposes , but since the ratio (["Base"])/(["Salt"]) for (["Salt"])/(["Acid"]) changes, a slight decrease or increase in pH results. The ratio of pH of solution (I) containing 1 mole of CH_(3)COONa and 1 mole of acetic acid in one litre is

The pH of basic buffer mixtures is given by pH = pK_(a) + log.(["Base"

1.	The pH of basic buffer mixtures is given by pH = pK_(a) + log.(["Base"])/(["Salt"]), whereas pH of acidic buffer mixtures is given by : pH = pK_(1) + log.(["Salt"])/(["Acid"]). Addition of little acid or base although shows no change in pH for all practical purposes , but since the ratio (["Base"])/(["Salt"]) for (["Salt"])/(["Acid"]) changes, a slight decrease or increase in pH results. The ratio of pH of solution (I) containing 1 mole of CH_(3)COONa and 1 mole of acetic acid in one litre is
Answer» `1:2` `2:1` `1:3` `3:1` SOLUTION :`{:(CH_(3)COONa+,HCl rarr,CH_(3)COOH+,NaCl,),(""1," "1,""0," "0,),(""0," "0,""1," "1,):}` `:. [CH_(3)COOH] = (1)/(2) =1`. `:. [H^(+)] = C alpha = C sqrt((K_(a))/(C)) = sqrt(K_(a).C) = sqrt(K_(a))` or `pH_(1) = -(1)/(2) LOG K_(a) = (1)/(2) pK_(a)` `{:(CH_(3)COOH+,CH_(3)COONa),(""1," "1):}` `:. pH = pK_(a) + log.(1)/(1) rArr pH_(2) = pK_(a) :. (pH_(1))/(pH_(2)) = (1)/(2)`.