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The ph of blood stream is maintained by a proper balance of H_(2)CO_(3) and NaHCO_(3) concentrations. What volume of 5M NaHCO_(3) solution, should be mixed with 10mL sample of blood which is 2M in H_(2)CO_(3) in order to maintain a pH of 7.4.K_(a) for H_(2)CO_(3) in blood is 4.0 xx 10^(-7)? |
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Answer» Solution :`[H_(2)CO_(3)]` in blood `=2M [NaHCO_(3)] = 5M` VOLUME of blood `= 10mL` Let volume of `NaHCO_(3)` used `= VmL` `[H_(2)CO_(3)]` in mixture =` (2xx10)/((V +10))` `[NaHCO_(3)]` in mixture `= ((5xxV))/((V +10))` `pH = pK_(a) + log .(["salt"])/(["acid"])` `7.4 = - log 4.0 XX 10^(-7) + "log"((5xxV)//(V+10))/((2xx10)//(V+10))` `V = 40mL` |
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