1.

The pH of pure water or neutral solution at 50^@C is………..

Answer»

`7.0`
`7.13`
`6.0`
`6.63`

Solution :`[H^+][OH^-]=10^(-13.26)`
`THEREFORE [H^+]=[OH^-]`
`[H^+]^2=10^(-13.26)`
`[H^+]=10^((-13.26)/2)`
`therefore pH=6.63`


Discussion

No Comment Found

Related InterviewSolutions