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The pH of solution obtained by mixing equal volumes of two aqueous solutions of pH 5 and pH 3 of the same substance is : |
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Answer» `3.5` `[H^(+)]` in solution of pH = 5 is `10^(-5)` `[H^(+)]` in solution of pH = 3 is `10^(-3)` TOTAL `[H^(+)]=10^(-5)+10^(-3)` `=1.01xx10^(-3)` Total VOLUME = 2000 ml Conc. in mixture `=(1.01xx10^(-3)xx1000)/(2000)=5.05xx10^(-4)` `pH=-log(5.05xx10^(-4))=3.3` |
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