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The pH of sulphuric acid solution is 2.3. What is the molar concentration of the acid ? |
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Answer» Solution :For sulphuric acid solution, pH = 2.3 `[H^(+)] = 10^(-pH) = 10^(-2.3)= 10^(-3)xx 10^(0.7)= 5 xx 10^(-3) mol L^(-1)` For sulphuric acid solution, `[H^+ ] = 2[H_2 SO_4 ]` MOLAR concentration of `H_2 SO_4 =([H^(+)])/(2)= ( 5 xx 10^(-3))/(2) = 2.5 xx 10^(-3) mol L^(-1)` |
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