1.

The pH of the aqueous solution containing 0.49 gm of H_(2)SO_(4) in one litre is

Answer»

2
1
1.7
0.3

Solution :Moles of `H_(2)SO_(4) = (0.49)/(98) = 5 xx 10^(-3)` moles of `H_(2)SO_(4)` PERCENT per litre of solution (MOLARITY) = `(0.005)/(1) = 0.005 M`.
`H_(2)SO_(4) + 2H_(2)O hArr 2H_(3)O^(+) + SO_(4)^(--)`.
one mole of `H_(2)SO_(4)` give 2 moles of `H_(3)O^(+)` ions.
`H_(3)O^(+) = 2 xx (H_(2)SO_(4)) = 2 xx 0.005 xx 0.01 M`
`[H^(+)] = 10^(-2)M , pH = 2`.


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