1.

The pH of the resultant solution of 20 ml of 0.1 M H_3PO_4 and 20 ml 0.1 M Na_3PO_4is

Answer»

` pK_(A1) +log 2 `
` pK_(al) `
` pK_(a_2)`
`(pK_(a1)+pK_(a_2))/(2)`

SOLUTION :` {:( H_3PO_4 +, PO_4^(-3)HARR, H_2PO_4^(-), +HPO_4^(-2) ),( 2 meq , 2meq ,0,0) :}`
` pH =P^(Ka_2) +log ""(2)/(2), pH =p^(Ka_2)`


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