1.

The pH of the solution: 5ml of (M)/(5), HCl + 10 ml of (M)/(10) NaOH is

Answer»

5
3
7
8

Solution :MILLIEQUIVALENTS of HCl `= 5 xx (1)/(5) = 1`.
Millequivalents of `NAOH = 10 xx (1)/(10) = 1`
`:. 5ML (M)/(5)HCl = 10 ml(M)/(10) NaOH`
Hence the solution will be neutral i.e, PH = 7.


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