1.

The pH of the solution containing 10 mL of 0.1 N NaOH and 10 mLof 0.05 NH_(2)SO_(4)would be

Answer»

1
0
7
` gt 7`

SOLUTION :Numberof milliequivalents of NaOH
= NORMALITY `xx` volume (mL)= `0.1 xx 10 =1 `
Numberof milliequivalents of ` H_(2)SO_(4) = 0.05 xx 10 = 0.5 `
0.5 milliequivalentof ` H_(2)SO_(4)`gets neutralized with contains0.5milliequivalentof NaOH. Hencesolution will be basicwithPH > 7


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