1.

The pH of the solution containing 10 ml of 0.1 N NaOH and 10 ml of 0.05 NH_(2)SO_(4) would be

Answer»

0
1
`gt 7`
7

Solution :M.eq of 10 ml, `0.1 N NAOH = 10 xx 0.1 = 1`
and M.eq. of 10 ml `0.05N H_(2)SO_(4) = 0.05 xx 10 = .5`
REMAINING M.eq. of `NaOH = 1 - 0.5 = 0.5`
`[OH^(-)] = (0.5)/(20 xx 10) = (1)/(40) = 0.25 xx 10^(-1) = 2.5 xx 10^(-2)`
`POH = - LOG 2.5 xx 10^(-2)`
`pOH = 0.2 - log 2.5`
`pH = 14 - pOH`
`pH = 14-2+log 2.5`
`pH = 12 + log 2.5 gt 7`


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