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The pH of the solution formed on mixing 20 mL of `0.05 M H_(2)SO_(4)` with 5.0 mL of 0.45 M NaOH of 298 K isA. 6B. 2C. 12D. 7 |
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Answer» Correct Answer - C `2 NaOH+H_(2)SO_(4)rarrNa_(2)SO_(4)+2H_(2)O` 20 mL of 0.05 M `H_(2)SO_(4)=20xx0.05` millimoles = 1 millimole 5 mL of 0.45 M NaOH `= 5 xx 0.45` millimoles `=2.25` millimole 2 millimoles of NaOH react with 1 millimole of `H_(2)SO_(4)` `:.` NaOH left in the solution = 0.5 millimole Volume of solution = 25 mL `:. [OH^(-)]= (0.5)/(25)M = 0.01 M = 10^(-2)M` `:. [H^(+)]=10^(-12) ` or pH = 12 |
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