The pH of the solution formed on mixing 20 mL of0.05 MH_(2)SO_(4) with 5.0 mL of 0.45 M NaOH of 298 K is

The pH of the solution formed on mixing 20 mL of0.05 MH_(2)SO_(4) with

1.	The pH of the solution formed on mixing 20 mL of0.05 MH_(2)SO_(4) with 5.0 mL of 0.45 M NaOH of 298 K is
Answer» 6 2 12 7 SOLUTION :`2 NAOH+H_(2)SO_(4)rarrNa_(2)SO_(4)+2H_(2)O` 20 mLof 0.05 M `H_(2)SO_(4)=20xx0.05` millimoles = 1 millimole 5 mL of 0.45 M NaOH `= 5 xx 0.45` millimoles `=2.25` millimole 2 millimoles of NaOH REACT with 1 millimole of `H_(2)SO_(4)` `:.` NaOH left in the solution = 0.5 millimole Volume of solution = 25 mL `:. [OH^(-)]= (0.5)/(25)M = 0.01 M = 10^(-2)M` `:. [H^(+)]=10^(-12) ` or pH = 12