The pH of the solution produced by mixing equal volumes of 2.0xx10^(-3) MCHlO_(4) and 1.0xx10^(-2) MKClO_(4) is

The pH of the solution produced by mixing equal volumes of 2.0xx10^(-3

1.	The pH of the solution produced by mixing equal volumes of 2.0xx10^(-3) MCHlO_(4) and 1.0xx10^(-2) MKClO_(4) is
Answer» `2.7` `2.3` `3.0` `1.0` Solution :`H^(+)` ions are obtained only from `HClO_(4)` which ionizes completely (being a STRONG acid ). Equal volume of `KClO_(4)` solution ADDED REDUCES `[H^(+)]` ions to HALF 3.0 . Hence, `[H^(+)]=(2xx10^(-3))/(2) :. pH = - log (10^(-3))=3.0`.