1.

The pH of the solution produced by mixing equal volume of 2.0 xx 10^(-3) M HClO_(4) and 1.0 xx 10^(-2) M KClO_(4) is

Answer»

2.7
2.3
3
1

Solution :`H^(+)` contribution is by ACID only as `KClO_(4)` is a SALT of a STRONG acid and strong base which does not hydrolyse.
So, `pH = -LOG[2.0 xx 10^(-3)]`
`= 3- log 2.0 = 3 - 0.3010 = 27`.


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