1.

The pH value of decinormal solution of NH_(4)OH which is 20% ionised, is

Answer»

`13.30`
`14.70`
`12.30`
`12.95`

SOLUTION :For `NH_(4)OH`.
`[OH^(-)] = C.alpha , c = (1)/(10)M, alpha = 0.2`
`[OH^(-)] = (1)/(10) xx 0.2 = 2 xx 10^(-2)M`
`pOH = - LOG [OH^(-)] = log[2 xx 10^(-2)], pOH = 1.7`
`pH = 14 - pOH = 14-1.7 = 12.30`.


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