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The photon emitted due to electronic transition of `5^(th)` excited state to `2^(nd)` excited state in `Li^(2+)`, is used to excite `He^+` already in first excited state.`He^+` ion after absorbing the photon reaches in an orbit having total energy equal to :A. `-3.4 eV`B. `-13.6 eV`C. `-6.8 eV`D. `-27.2 eV` |
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Answer» Correct Answer - A (A)For `Li^(2+)`, n=6 to n=3 For H, the similar transition is 2 to 1 For `He^+` , the similar transition is 4 to 2 Energy of `4^(th)` orbit of `He^(+)` =`-13.6xx2^2/4^2= -3.4 eV` |
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