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The pilot of an aeroplane flying horizontally at a height of 2000m with a constant speed of 540 kmph wishes to hit a target on the ground . At what distance from the target should release the bomb to hitthe target ? |
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Answer» Solution :Given : Initialof the bomb in the horizontal is the same as that of the aeroplane . Initial velcoity of the bomb in the horizontal direction = 540 KMPH ` = 540 xx (5)/( 18) ms^(-1)` `= 150 ms^(-1)` Initial velocity in the vertical direction (u) = 0 `{:("Vertical"),("distance(s)"):}} = 2000 m ` , TIME of FLIGHT t = ? ` s = ut +(1)/(2) at^(2)` Substituting the known values , ` 2000 = 0 xx t +(1)/(2) xx 9 . 8 xx t^(2)` ` 2000 = 4.9 t^(2)` (or) `t = sqrt((2000)/( 4 . 9)) = 20 . 20 s` `:.{:("Horizontal"),("range"):}} = {{:("Horizontal velocity"),(xx "time of flight"):}` ` = 150 xx 20 . 20 = 3 030 m `
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