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The pK_a of a weak acid (HA) is 4.5. The pOH of an aqueous buffered solution of HA in which 50 % of the acid is ionized is |
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Answer» `7.0` When the ACID is 50% ionised , `[A^-]=[HA]` or pH=`pK_a+log 1` or pH = `pK_a` Given `pK_a=4.5` `therefore` pH=9.5 `therefore` pOH=14-4.5=9.5 |
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