1.

The pK_a of a weak acid (HA) is 4.5. The pOH of an aqueous buffered solution of HA in which 50 % of the acid is ionized is

Answer»

`7.0`
`4.5`
`2.5`
`9.5`

SOLUTION :For acidic buffer, `pH=pK_a+"LOG" ([A^-])/([HA])`
When the ACID is 50% ionised , `[A^-]=[HA]`
or pH=`pK_a+log 1` or pH = `pK_a`
Given `pK_a=4.5`
`therefore` pH=9.5
`therefore` pOH=14-4.5=9.5


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