1.

The pK_(a) of a weak acid (HA) is 4.5 the pOH of an aqueous buffered solution of HA in which 50% of the acid is ionized is

Answer»

4.5
2.5
9.5
`7.0`

Solution :For buffer solution
`PH = pK_(a) + log.(["SALT"])/(["Acid"]) = 4.5 + log.(["Salt"])/(["Acid"])`
as HA is 50% ionized so [Salt] = [Acid]
pH = 4.5
pH + pOH = 14
`rArr pOH = 14 - 4.5 = 9.5`.


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