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The `pK_(a)` of a weak acid (HA) is 4.5 the pOH of an aqueous buffered solution of HA in which 50% of the acid is ionized isA. 4.5B. 2.5C. 9.5D. `7.0` |
Answer» Correct Answer - C For buffer solution `pH = pK_(a) + log.(["Salt"])/(["Acid"]) = 4.5 + log.(["Salt"])/(["Acid"])` as HA is 50% ionized so [Salt] = [Acid] pH = 4.5 pH + pOH = 14 `rArr pOH = 14 - 4.5 = 9.5`. |
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