1.

The pk_(a) of a weak acid, HA is 4.8. The pK_(b) of a weak base, BOH is 4.78. The pH of an aqueous solution of the corresponding salt, BA will be

Answer»

4.79
7.01
9.22
9.58

Solution :`pK_(a) = 4.8 , pK_(B) = 4.78`
`PH = 7+(1)/(2)(pK_(a) - pK_(b)) = 7 + (1)/(2)(4.8 - 4.78) = 7.01`.


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