The pK_a of a weak acid, HA, is 4.80. The pK_b of a weak base, BOH is 4.78. The pH of an aqueous solution of the corresponding salt BA, will be

The pK_a of a weak acid, HA, is 4.80. The pK_b of a weak base, BOH is

1.	The pK_a of a weak acid, HA, is 4.80. The pK_b of a weak base, BOH is 4.78. The pH of an aqueous solution of the corresponding salt BA, will be
Answer» 9.22 9.58 4.79 7.01 Solution :Given that `pK_a`=4.8 and `pK_b`= 4.78 `therefore` pH=7+1/2 `(pK_a-pK_b)` =7+1/2(4.80+4.78) =7.01 `K_2=([CO][H_2]^3)/([CO_4][H_2O])`…(2) `CH_(4(G)) + 2H_2O_((g)) hArr CO_(2(g)) + 4H_(2(g))` `K_3=([CO_2][H_2]^4)/([CO_4][H_2O]^2)` ....(3)