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The pK_(a) of an acid HA is 4.77 and pK_(b) of a base BOH is 4.75 . The pH of 0.1 M aqueoussolutionof the salt AB is |
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Answer» 7.02 `pH = 7 + (1)/(2) (pK_(a)-pK_(b))` `=7 + (1)/(2) (4.77-4.75)= 7.01` |
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