1.

The pK_(a) of weak acid (HA) is 4.5 . The pOH of an aqueous buffered solution of HA is which 50% of the acid is ionized is

Answer»

`7.0`
`4.5`
`2.5`
`9.5`

SOLUTION :When HA is 50% ionized , [HA] = `[A^(-)]`
`PH = pK_(a)+log .([A^(-)])/([HA])=pK_(a)=4.5 ` (Given)
`pOH = 14- pH = 14 - 4.5 = 9.5.


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