1.

The pK_(a0 of a weak acid (HA) is 4.5. The pOH of an aqueous buffered solution of HA in which 50% of the acid is ionized is :

Answer»

`2.5`
`9.5`
`7.0`
`4.5`

SOLUTION :If the given WEAK acid is 50% ionised then its conjugate BASE will have the CONCENTRATION same as that of weak acid.
`pH=pK_(a)+"log"(["conjugate base"])/(["Acid"])`
`=4.5+"log"(0.5c)/(0.5c)=4.5`
`therefore POH = 14-4.5=9.5`


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