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The pKa of weak acid is 4.3. 600 ml of 0.1 M weak acid HA is added to 250 ml of 0.2 M NaOH. The pOH of resulting solution is : (log5 = 0.7)

Answer» Correct Answer - 7
The E.C. of element = [Ar] `3d^(5)4s^(2)`, Group = `7^(th)`


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