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The plane passes through the point (1,-1,-1) and its normal is perpendicular to both the lines (x-1)/(1) = (y+2)/(-2) = (z-4)/(3) and (x-2)/(2) + (y+1)/(-1) = (z+7)/(-1). The distance of the point (1,3,-7) from thise plane is .......... |
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Answer» `(10)/(SQRT(74))` |
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