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The plastic industry uses large amounts of phthalic anhydride `C_(8)H_(4)O_(3)`, made by the controlled `C_(10) H_(8) + (9)/(2) O_(2) rarr C_(8) H_(4) O_(3) + 2 CO_(2) + (5)/(2) H_(2) O` Since some of the naphthalene is oxidised to other products, 80% yield is obtained. What weight of phthalic anhydrid would be produced by the oxidation of `256 g` of `C_(10)H_(8)`. `[Mw "of" C_(10) H_(8) = 128, Mw "of" C_(8) H_(4) O_(3) = 148]` |
Answer» `128 g of C_(10 H_(8)` gives `= 148 g of C_(8) H_(4) O_(3)` `256 g of C_(10) H_(8)` gives ` = (148 xx 256)/(128) = 296 g` Actual weight of `C_(8) H_(4) O_(3) = (296 xx 80)/(100) = 236.8 g` `C_(8) H_(4) O_(3)` produced |
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