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The plates of a parallel plate capacitor have an area of 100 cm2 each of 100 cm2 each and are separated by 3 mm. The capacitor is charged by connecting it to a 400 V supply. a) Calculate the electrostatic energy stored in the capacitor. b) If a dielectric of dielectric constant 2.5 is introduced between the plates of the capacitor, then find the electrostatic. |
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Answer» energy stored and also change in the energy stored. Given A = 100 cm2 = 100 x 10–4m2, d = 3 mm = 3 x 10–3m, V = 400 V, U1 = ? K = 2.5, U2 = ? also U2 – U1 = ? U = \(\frac{1}{2}CV^2\) C = \(\frac{\varepsilon_0 A}{d}\) Calculating U1 = 23.608 x 10–7J U2 = 59.02 x 10–7J U2 ∼ U1 = 35.412 x 10–7J |
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