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The pOH of a solution is 5.725. Calculate the [H^(+)]. |
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Answer» Solution :`pH+pOH=14""pH=14-pOH=14-5.725=8.275` `pH=-log_(10)[H^(+)]rArr8.275=log_(10)[H^(+)]RARR` `[H^(+)]="anti"LOG(-8.275)="anti"log(9-8.275-9)` `[H^(+)]="anti"log(0.275-9)=5.309xx10^(-9)"mol"dm^(-3)` |
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