1.

The pOH of a solution is 5.725. Calculate the [H+].

Answer»

pH + pOH = 14 pH = 14 – pOH = 14 – 5.725 = 8.275

pH = -log10[H+] ⇒ 8.275 = log10[H+

⇒ [H+] = antilog (-8.275) = antilog(9 – 8.275 – 9)

[H+] = antilog (0.275 – 9) = 5.309 × 10-9 mol dm-3.



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