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The point from which the tangents to the circles x2+y2–8x+40=0,5x2+5y2–25x+80=0,x2+y2–8x+16y+160=0 are equal in length is |
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Answer» The point from which the tangents to the circles x2+y2–8x+40=0,5x2+5y2–25x+80=0,x2+y2–8x+16y+160=0 are equal in length is |
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