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The point of inflection of the function y = ∫(t2 - 3t + 2)dt x ∈[0,x] is :(A) (1/2, 3/2)(B) (3/2, 3/4)(C) (-3/2, -3/4)(D) (-1/2, - 3/2) |
Answer» Correct option (B) (3/2, 3/4) Explanation: Given y = ∫(t2 - 3t + 2)dt x ∈[0,x } Differentiating w.r.to x, we have dy/dx = x2- 3x + 2 & d2y/dx2 = 2x -3. At the point of inflection d2y/dx2 = 0 & second derivative changes sign while passing through the point of inflection. Clearly P(3/2, 3/4). |
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